[LeetCode]297. Serialize and Deserialize Binary Tree

序列化二叉树

Posted by JinFei on September 29, 2021

题目描述

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.

Example1:

  You may serialize the following tree:
     1
    / \
    2   3
        / \
        4   5

    as "[1,2,3,null,null,4,5]"

Clarification:

The above format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.

Note:

Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.

解题思路

  • 序列化与反序列化二叉树
  • 注意反序列化二叉树时,需要传一个当前的位置
  • 并且需要注意 值为负数的情况,不能用 val = val * 10 + data[index] -‘0’
  • 应该用string内置的函数 stoi
  • 序列化,防止出现负数
  • 第二个传的应该是个引用
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Codec {
public:

    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        if(root == nullptr){
            return "";
        }
        string str;
        fun_serialize(root, str);
        return str;
    }
    void fun_serialize(TreeNode* root, string& str){
        if(root == nullptr){
            str += "#";
            return;
        }
        str += to_string(root -> val);
        str += ",";
        fun_serialize(root -> left, str);
        fun_serialize(root -> right, str);
    }

    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        if(data.size() == 0){
            return nullptr;
        }
        int pos = 0;
        return fun_deserialize(data, pos);
    }
    TreeNode* fun_deserialize(string data, int& pos){
        if(data[pos] == '#'){
            pos += 1;
            return nullptr;
        }
        int index = pos;
        int val = 0;
        while(data[index] != ','){
            index++;
        }
    
        val = stoi(data.substr(pos, index - pos));  // 注意这一点,不应该用 连乘法
        TreeNode* root = new TreeNode(val);
        pos = index + 1;
        
        root -> left = fun_deserialize(data, pos);
        root -> right = fun_deserialize(data, pos);
        return root;
    }
};

// Your Codec object will be instantiated and called as such:
// Codec codec;
// codec.deserialize(codec.serialize(root));

另外一版代码

// Author: Huahua
// Running time: 39 ms
class Codec {
public:
 
    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        ostringstream out;
        serialize(root, out);
        return out.str();
    }
 
    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        istringstream in(data);
        return deserialize(in);
    }
private:
    void serialize(TreeNode* root, ostringstream& out) {
        if (!root) {
            out << "# ";
            return;
        }        
        out << root->val << " ";
        serialize(root->left, out);
        serialize(root->right, out);
    }
    
    TreeNode* deserialize(istringstream& in) {
        string val;
        in >> val;
        if (val == "#") return nullptr;        
        TreeNode* root = new TreeNode(stoi(val));        
        root->left = deserialize(in);
        root->right = deserialize(in);        
        return root;
    }
};